3.136 \(\int \frac {(a g+b g x)^2 (A+B \log (e (\frac {a+b x}{c+d x})^n))}{c i+d i x} \, dx\)

Optimal. Leaf size=211 \[ -\frac {g^2 (b c-a d)^2 \log \left (\frac {b c-a d}{b (c+d x)}\right ) \left (2 B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+2 A+3 B n\right )}{2 d^3 i}-\frac {g^2 (a+b x) (b c-a d) \left (2 B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+2 A+B n\right )}{2 d^2 i}+\frac {g^2 (a+b x)^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{2 d i}-\frac {B g^2 n (b c-a d)^2 \text {Li}_2\left (\frac {d (a+b x)}{b (c+d x)}\right )}{d^3 i} \]

[Out]

1/2*g^2*(b*x+a)^2*(A+B*ln(e*((b*x+a)/(d*x+c))^n))/d/i-1/2*(-a*d+b*c)*g^2*(b*x+a)*(2*A+B*n+2*B*ln(e*((b*x+a)/(d
*x+c))^n))/d^2/i-1/2*(-a*d+b*c)^2*g^2*(2*A+3*B*n+2*B*ln(e*((b*x+a)/(d*x+c))^n))*ln((-a*d+b*c)/b/(d*x+c))/d^3/i
-B*(-a*d+b*c)^2*g^2*n*polylog(2,d*(b*x+a)/b/(d*x+c))/d^3/i

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Rubi [A]  time = 0.49, antiderivative size = 343, normalized size of antiderivative = 1.63, number of steps used = 18, number of rules used = 13, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.302, Rules used = {2528, 2486, 31, 2525, 12, 43, 2524, 2418, 2394, 2393, 2391, 2390, 2301} \[ -\frac {B g^2 n (b c-a d)^2 \text {PolyLog}\left (2,\frac {b (c+d x)}{b c-a d}\right )}{d^3 i}+\frac {g^2 (b c-a d)^2 \log (c i+d i x) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{d^3 i}+\frac {g^2 (a+b x)^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )}{2 d i}-\frac {A b g^2 x (b c-a d)}{d^2 i}-\frac {B g^2 (a+b x) (b c-a d) \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{d^2 i}-\frac {b B g^2 n x (b c-a d)}{2 d^2 i}+\frac {B g^2 n (b c-a d)^2 \log ^2(i (c+d x))}{2 d^3 i}+\frac {3 B g^2 n (b c-a d)^2 \log (c+d x)}{2 d^3 i}-\frac {B g^2 n (b c-a d)^2 \log (c i+d i x) \log \left (-\frac {d (a+b x)}{b c-a d}\right )}{d^3 i} \]

Antiderivative was successfully verified.

[In]

Int[((a*g + b*g*x)^2*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/(c*i + d*i*x),x]

[Out]

-((A*b*(b*c - a*d)*g^2*x)/(d^2*i)) - (b*B*(b*c - a*d)*g^2*n*x)/(2*d^2*i) - (B*(b*c - a*d)*g^2*(a + b*x)*Log[e*
((a + b*x)/(c + d*x))^n])/(d^2*i) + (g^2*(a + b*x)^2*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/(2*d*i) + (3*B*(b
*c - a*d)^2*g^2*n*Log[c + d*x])/(2*d^3*i) + (B*(b*c - a*d)^2*g^2*n*Log[i*(c + d*x)]^2)/(2*d^3*i) - (B*(b*c - a
*d)^2*g^2*n*Log[-((d*(a + b*x))/(b*c - a*d))]*Log[c*i + d*i*x])/(d^3*i) + ((b*c - a*d)^2*g^2*(A + B*Log[e*((a
+ b*x)/(c + d*x))^n])*Log[c*i + d*i*x])/(d^3*i) - (B*(b*c - a*d)^2*g^2*n*PolyLog[2, (b*(c + d*x))/(b*c - a*d)]
)/(d^3*i)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rule 2486

Int[Log[(e_.)*((f_.)*((a_.) + (b_.)*(x_))^(p_.)*((c_.) + (d_.)*(x_))^(q_.))^(r_.)]^(s_.), x_Symbol] :> Simp[((
a + b*x)*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^s)/b, x] + Dist[(q*r*s*(b*c - a*d))/b, Int[Log[e*(f*(a + b*x)^p*
(c + d*x)^q)^r]^(s - 1)/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, p, q, r, s}, x] && NeQ[b*c - a*d, 0] &&
EqQ[p + q, 0] && IGtQ[s, 0]

Rule 2524

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[d + e*x]*(a + b
*Log[c*RFx^p])^n)/e, x] - Dist[(b*n*p)/e, Int[(Log[d + e*x]*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x
] /; FreeQ[{a, b, c, d, e, p}, x] && RationalFunctionQ[RFx, x] && IGtQ[n, 0]

Rule 2525

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Simp[((d + e*x)^(m
+ 1)*(a + b*Log[c*RFx^p])^n)/(e*(m + 1)), x] - Dist[(b*n*p)/(e*(m + 1)), Int[SimplifyIntegrand[((d + e*x)^(m +
1)*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && RationalFunc
tionQ[RFx, x] && IGtQ[n, 0] && (EqQ[n, 1] || IntegerQ[m]) && NeQ[m, -1]

Rule 2528

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With[{u = ExpandIntegrand[(a + b*Log[c*
RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalF
unctionQ[RGx, x] && IGtQ[n, 0]

Rubi steps

\begin {align*} \int \frac {(a g+b g x)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{136 c+136 d x} \, dx &=\int \left (-\frac {b (b c-a d) g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{136 d^2}+\frac {(b c-a d)^2 g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{d^2 (136 c+136 d x)}+\frac {b g (a g+b g x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{136 d}\right ) \, dx\\ &=\frac {(b g) \int (a g+b g x) \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \, dx}{136 d}-\frac {\left (b (b c-a d) g^2\right ) \int \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \, dx}{136 d^2}+\frac {\left ((b c-a d)^2 g^2\right ) \int \frac {A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{136 c+136 d x} \, dx}{d^2}\\ &=-\frac {A b (b c-a d) g^2 x}{136 d^2}+\frac {g^2 (a+b x)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{272 d}+\frac {(b c-a d)^2 g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (136 c+136 d x)}{136 d^3}-\frac {\left (b B (b c-a d) g^2\right ) \int \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right ) \, dx}{136 d^2}-\frac {(B n) \int \frac {(b c-a d) g^2 (a+b x)}{c+d x} \, dx}{272 d}-\frac {\left (B (b c-a d)^2 g^2 n\right ) \int \frac {(c+d x) \left (-\frac {d (a+b x)}{(c+d x)^2}+\frac {b}{c+d x}\right ) \log (136 c+136 d x)}{a+b x} \, dx}{136 d^3}\\ &=-\frac {A b (b c-a d) g^2 x}{136 d^2}-\frac {B (b c-a d) g^2 (a+b x) \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{136 d^2}+\frac {g^2 (a+b x)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{272 d}+\frac {(b c-a d)^2 g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (136 c+136 d x)}{136 d^3}-\frac {\left (B (b c-a d) g^2 n\right ) \int \frac {a+b x}{c+d x} \, dx}{272 d}-\frac {\left (B (b c-a d)^2 g^2 n\right ) \int \left (\frac {b \log (136 c+136 d x)}{a+b x}-\frac {d \log (136 c+136 d x)}{c+d x}\right ) \, dx}{136 d^3}+\frac {\left (B (b c-a d)^2 g^2 n\right ) \int \frac {1}{c+d x} \, dx}{136 d^2}\\ &=-\frac {A b (b c-a d) g^2 x}{136 d^2}-\frac {B (b c-a d) g^2 (a+b x) \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{136 d^2}+\frac {g^2 (a+b x)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{272 d}+\frac {B (b c-a d)^2 g^2 n \log (c+d x)}{136 d^3}+\frac {(b c-a d)^2 g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (136 c+136 d x)}{136 d^3}-\frac {\left (B (b c-a d) g^2 n\right ) \int \left (\frac {b}{d}+\frac {-b c+a d}{d (c+d x)}\right ) \, dx}{272 d}-\frac {\left (b B (b c-a d)^2 g^2 n\right ) \int \frac {\log (136 c+136 d x)}{a+b x} \, dx}{136 d^3}+\frac {\left (B (b c-a d)^2 g^2 n\right ) \int \frac {\log (136 c+136 d x)}{c+d x} \, dx}{136 d^2}\\ &=-\frac {A b (b c-a d) g^2 x}{136 d^2}-\frac {b B (b c-a d) g^2 n x}{272 d^2}-\frac {B (b c-a d) g^2 (a+b x) \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{136 d^2}+\frac {g^2 (a+b x)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{272 d}+\frac {3 B (b c-a d)^2 g^2 n \log (c+d x)}{272 d^3}-\frac {B (b c-a d)^2 g^2 n \log \left (-\frac {d (a+b x)}{b c-a d}\right ) \log (136 c+136 d x)}{136 d^3}+\frac {(b c-a d)^2 g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (136 c+136 d x)}{136 d^3}+\frac {\left (B (b c-a d)^2 g^2 n\right ) \operatorname {Subst}\left (\int \frac {136 \log (x)}{x} \, dx,x,136 c+136 d x\right )}{18496 d^3}+\frac {\left (B (b c-a d)^2 g^2 n\right ) \int \frac {\log \left (\frac {136 d (a+b x)}{-136 b c+136 a d}\right )}{136 c+136 d x} \, dx}{d^2}\\ &=-\frac {A b (b c-a d) g^2 x}{136 d^2}-\frac {b B (b c-a d) g^2 n x}{272 d^2}-\frac {B (b c-a d) g^2 (a+b x) \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{136 d^2}+\frac {g^2 (a+b x)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{272 d}+\frac {3 B (b c-a d)^2 g^2 n \log (c+d x)}{272 d^3}-\frac {B (b c-a d)^2 g^2 n \log \left (-\frac {d (a+b x)}{b c-a d}\right ) \log (136 c+136 d x)}{136 d^3}+\frac {(b c-a d)^2 g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (136 c+136 d x)}{136 d^3}+\frac {\left (B (b c-a d)^2 g^2 n\right ) \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,136 c+136 d x\right )}{136 d^3}+\frac {\left (B (b c-a d)^2 g^2 n\right ) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {b x}{-136 b c+136 a d}\right )}{x} \, dx,x,136 c+136 d x\right )}{136 d^3}\\ &=-\frac {A b (b c-a d) g^2 x}{136 d^2}-\frac {b B (b c-a d) g^2 n x}{272 d^2}-\frac {B (b c-a d) g^2 (a+b x) \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )}{136 d^2}+\frac {g^2 (a+b x)^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right )}{272 d}+\frac {3 B (b c-a d)^2 g^2 n \log (c+d x)}{272 d^3}+\frac {B (b c-a d)^2 g^2 n \log ^2(136 (c+d x))}{272 d^3}-\frac {B (b c-a d)^2 g^2 n \log \left (-\frac {d (a+b x)}{b c-a d}\right ) \log (136 c+136 d x)}{136 d^3}+\frac {(b c-a d)^2 g^2 \left (A+B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )\right ) \log (136 c+136 d x)}{136 d^3}-\frac {B (b c-a d)^2 g^2 n \text {Li}_2\left (\frac {b (c+d x)}{b c-a d}\right )}{136 d^3}\\ \end {align*}

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Mathematica [A]  time = 0.19, size = 266, normalized size = 1.26 \[ \frac {g^2 \left (d^2 (a+b x)^2 \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )+2 (b c-a d)^2 \log (i (c+d x)) \left (B \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )+A\right )-2 A b d x (b c-a d)+2 B d (a+b x) (a d-b c) \log \left (e \left (\frac {a+b x}{c+d x}\right )^n\right )-B n (b c-a d)^2 \left (\log (i (c+d x)) \left (2 \log \left (\frac {d (a+b x)}{a d-b c}\right )-\log (i (c+d x))\right )+2 \text {Li}_2\left (\frac {b (c+d x)}{b c-a d}\right )\right )+2 B n (b c-a d)^2 \log (c+d x)-B n (b c-a d) ((a d-b c) \log (c+d x)+b d x)\right )}{2 d^3 i} \]

Antiderivative was successfully verified.

[In]

Integrate[((a*g + b*g*x)^2*(A + B*Log[e*((a + b*x)/(c + d*x))^n]))/(c*i + d*i*x),x]

[Out]

(g^2*(-2*A*b*d*(b*c - a*d)*x + 2*B*d*(-(b*c) + a*d)*(a + b*x)*Log[e*((a + b*x)/(c + d*x))^n] + d^2*(a + b*x)^2
*(A + B*Log[e*((a + b*x)/(c + d*x))^n]) + 2*B*(b*c - a*d)^2*n*Log[c + d*x] - B*(b*c - a*d)*n*(b*d*x + (-(b*c)
+ a*d)*Log[c + d*x]) + 2*(b*c - a*d)^2*(A + B*Log[e*((a + b*x)/(c + d*x))^n])*Log[i*(c + d*x)] - B*(b*c - a*d)
^2*n*((2*Log[(d*(a + b*x))/(-(b*c) + a*d)] - Log[i*(c + d*x)])*Log[i*(c + d*x)] + 2*PolyLog[2, (b*(c + d*x))/(
b*c - a*d)])))/(2*d^3*i)

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fricas [F]  time = 1.03, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {A b^{2} g^{2} x^{2} + 2 \, A a b g^{2} x + A a^{2} g^{2} + {\left (B b^{2} g^{2} x^{2} + 2 \, B a b g^{2} x + B a^{2} g^{2}\right )} \log \left (e \left (\frac {b x + a}{d x + c}\right )^{n}\right )}{d i x + c i}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^2*(A+B*log(e*((b*x+a)/(d*x+c))^n))/(d*i*x+c*i),x, algorithm="fricas")

[Out]

integral((A*b^2*g^2*x^2 + 2*A*a*b*g^2*x + A*a^2*g^2 + (B*b^2*g^2*x^2 + 2*B*a*b*g^2*x + B*a^2*g^2)*log(e*((b*x
+ a)/(d*x + c))^n))/(d*i*x + c*i), x)

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giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^2*(A+B*log(e*((b*x+a)/(d*x+c))^n))/(d*i*x+c*i),x, algorithm="giac")

[Out]

Timed out

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maple [F]  time = 0.46, size = 0, normalized size = 0.00 \[ \int \frac {\left (b g x +a g \right )^{2} \left (B \ln \left (e \left (\frac {b x +a}{d x +c}\right )^{n}\right )+A \right )}{d i x +c i}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*g*x+a*g)^2*(B*ln(e*((b*x+a)/(d*x+c))^n)+A)/(d*i*x+c*i),x)

[Out]

int((b*g*x+a*g)^2*(B*ln(e*((b*x+a)/(d*x+c))^n)+A)/(d*i*x+c*i),x)

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maxima [B]  time = 4.69, size = 627, normalized size = 2.97 \[ 2 \, A a b g^{2} {\left (\frac {x}{d i} - \frac {c \log \left (d x + c\right )}{d^{2} i}\right )} + \frac {1}{2} \, A b^{2} g^{2} {\left (\frac {2 \, c^{2} \log \left (d x + c\right )}{d^{3} i} + \frac {d x^{2} - 2 \, c x}{d^{2} i}\right )} + \frac {A a^{2} g^{2} \log \left (d i x + c i\right )}{d i} + \frac {{\left (b^{2} c^{2} g^{2} n - 2 \, a b c d g^{2} n + a^{2} d^{2} g^{2} n\right )} {\left (\log \left (b x + a\right ) \log \left (\frac {b d x + a d}{b c - a d} + 1\right ) + {\rm Li}_2\left (-\frac {b d x + a d}{b c - a d}\right )\right )} B}{d^{3} i} + \frac {{\left (2 \, a^{2} d^{2} g^{2} \log \relax (e) + {\left (3 \, g^{2} n + 2 \, g^{2} \log \relax (e)\right )} b^{2} c^{2} - 4 \, {\left (g^{2} n + g^{2} \log \relax (e)\right )} a b c d\right )} B \log \left (d x + c\right )}{2 \, d^{3} i} + \frac {B b^{2} d^{2} g^{2} x^{2} \log \relax (e) - 2 \, {\left (b^{2} c^{2} g^{2} n - 2 \, a b c d g^{2} n + a^{2} d^{2} g^{2} n\right )} B \log \left (b x + a\right ) \log \left (d x + c\right ) + {\left (b^{2} c^{2} g^{2} n - 2 \, a b c d g^{2} n + a^{2} d^{2} g^{2} n\right )} B \log \left (d x + c\right )^{2} - {\left ({\left (g^{2} n + 2 \, g^{2} \log \relax (e)\right )} b^{2} c d - {\left (g^{2} n + 4 \, g^{2} \log \relax (e)\right )} a b d^{2}\right )} B x - {\left (2 \, a b c d g^{2} n - 3 \, a^{2} d^{2} g^{2} n\right )} B \log \left (b x + a\right ) + {\left (B b^{2} d^{2} g^{2} x^{2} - 2 \, {\left (b^{2} c d g^{2} - 2 \, a b d^{2} g^{2}\right )} B x + 2 \, {\left (b^{2} c^{2} g^{2} - 2 \, a b c d g^{2} + a^{2} d^{2} g^{2}\right )} B \log \left (d x + c\right )\right )} \log \left ({\left (b x + a\right )}^{n}\right ) - {\left (B b^{2} d^{2} g^{2} x^{2} - 2 \, {\left (b^{2} c d g^{2} - 2 \, a b d^{2} g^{2}\right )} B x + 2 \, {\left (b^{2} c^{2} g^{2} - 2 \, a b c d g^{2} + a^{2} d^{2} g^{2}\right )} B \log \left (d x + c\right )\right )} \log \left ({\left (d x + c\right )}^{n}\right )}{2 \, d^{3} i} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^2*(A+B*log(e*((b*x+a)/(d*x+c))^n))/(d*i*x+c*i),x, algorithm="maxima")

[Out]

2*A*a*b*g^2*(x/(d*i) - c*log(d*x + c)/(d^2*i)) + 1/2*A*b^2*g^2*(2*c^2*log(d*x + c)/(d^3*i) + (d*x^2 - 2*c*x)/(
d^2*i)) + A*a^2*g^2*log(d*i*x + c*i)/(d*i) + (b^2*c^2*g^2*n - 2*a*b*c*d*g^2*n + a^2*d^2*g^2*n)*(log(b*x + a)*l
og((b*d*x + a*d)/(b*c - a*d) + 1) + dilog(-(b*d*x + a*d)/(b*c - a*d)))*B/(d^3*i) + 1/2*(2*a^2*d^2*g^2*log(e) +
(3*g^2*n + 2*g^2*log(e))*b^2*c^2 - 4*(g^2*n + g^2*log(e))*a*b*c*d)*B*log(d*x + c)/(d^3*i) + 1/2*(B*b^2*d^2*g^
2*x^2*log(e) - 2*(b^2*c^2*g^2*n - 2*a*b*c*d*g^2*n + a^2*d^2*g^2*n)*B*log(b*x + a)*log(d*x + c) + (b^2*c^2*g^2*
n - 2*a*b*c*d*g^2*n + a^2*d^2*g^2*n)*B*log(d*x + c)^2 - ((g^2*n + 2*g^2*log(e))*b^2*c*d - (g^2*n + 4*g^2*log(e
))*a*b*d^2)*B*x - (2*a*b*c*d*g^2*n - 3*a^2*d^2*g^2*n)*B*log(b*x + a) + (B*b^2*d^2*g^2*x^2 - 2*(b^2*c*d*g^2 - 2
*a*b*d^2*g^2)*B*x + 2*(b^2*c^2*g^2 - 2*a*b*c*d*g^2 + a^2*d^2*g^2)*B*log(d*x + c))*log((b*x + a)^n) - (B*b^2*d^
2*g^2*x^2 - 2*(b^2*c*d*g^2 - 2*a*b*d^2*g^2)*B*x + 2*(b^2*c^2*g^2 - 2*a*b*c*d*g^2 + a^2*d^2*g^2)*B*log(d*x + c)
)*log((d*x + c)^n))/(d^3*i)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a\,g+b\,g\,x\right )}^2\,\left (A+B\,\ln \left (e\,{\left (\frac {a+b\,x}{c+d\,x}\right )}^n\right )\right )}{c\,i+d\,i\,x} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a*g + b*g*x)^2*(A + B*log(e*((a + b*x)/(c + d*x))^n)))/(c*i + d*i*x),x)

[Out]

int(((a*g + b*g*x)^2*(A + B*log(e*((a + b*x)/(c + d*x))^n)))/(c*i + d*i*x), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)**2*(A+B*ln(e*((b*x+a)/(d*x+c))**n))/(d*i*x+c*i),x)

[Out]

Timed out

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